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vec(a)xx[vec(a)xx(vecaxxvecb)] is equal ...

`vec(a)xx[vec(a)xx(vecaxxvecb)]` is equal to

A

`(vecaxxveca).(vecbxxveca)`

B

`vec(a).(vec(a)xxvec(b))-vec(b)(vec(a)xxvec(b))`

C

`[vec(a).(vec(a)xxvec(b))]vec(a)`

D

`(vec(a).vec(a))(vec(b)xxvec(a))`

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The correct Answer is:
D
`vecaxx[veca xx (veca xx vecb)]`
`vecaxx{( veca* vecb) vec a-(veca* veca) vecb}`
`=(veca*vecb)(vecaxx veca)-(veca*veca)(vecaxx vecb)`
`=(veca*vecb)0+(veca*veca)(vecbxx veca)`
`=(veca*veca)(vecb xx veca)`
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