A ray of light is incident on a medium boundry at polarising angle such that its deviation is `24^(@)`, then angle of incidence is :

Options

A. `24^(@)`
B. `57^(@)`
C. `66^(@)`
D. `90^(@)`

Answer

B

Explanation

Here ` ,i_(p)=r+delta`

`i_(p)=r+24`................(i)
Moreover , `i_(p)+r =90^(@)` ................(ii)
From Eqs. (i) and (ii) , we get
`i_(p)+(i_p-24)=90^(@)`
`implies i_(p)=57^(@)`