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In a satellite if the time of revolution...

In a satellite if the time of revolution is `T`, then kinetic energy is proportional to

A

`(1)/(T)`

B

`(1)/(T^(2))`

C

`(1)/(T^(3))`

D

`T^(-2//3)`

Text Solution

Verified by Experts

The correct Answer is:
D

Velocity of satellite ` v =sqrt((GM)/(r))`
`:. KE prop v^(2) prop (1)/(r) and T^(2) prop r^(3)`
`:. Ke prop T^(-2//3)`
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