Home
Class 12
PHYSICS
If rho is the density of the planet , th...

If `rho` is the density of the planet , the time period of nearby satellite is given by

A

`sqrt((4pi)/(3G rho))`

B

`sqrt((4pi)/(G rho))`

C

`sqrt((3pi)/(G rho))`

D

`sqrt((pi)/(G rho))`

Text Solution

Verified by Experts

The correct Answer is:
C

Time period of nearby satellite
`T=2pi sqrt((r^(3))/(GM))`
`=2pi sqrt((R^(3))/(GM))`
`=(2 pi (R^(3))^(1//2))/([G*(4)/(3)piR^(3)rho]^(1//2))`
`=sqrt((3pi)/(G rho))`
Promotional Banner

Topper's Solved these Questions

  • MHTCET 2008

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise PHYSICS|49 Videos
  • MHTCET 2010

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise Physics|50 Videos

Similar Questions

Explore conceptually related problems

Define the time period of a satellite

The time period of a geostationary satellite is

A small satellite revolves round a planet in an orbit just above planet's surface. Taking the mean density of planet as rho , calculate the time period of the satellite.

" For a given density of planet,the orbital period of a satellite near the surface of the planet of radius "R" is proportional to "R^(N)" .Find the value of "Lambda

If satellite is shifted towards the earth. Then time period of satellite will be

The fastest possible of rotation of a planet is that for which the gravitational force on material at the equtor barely provides the centripetal force needed for the rotation. Show then that the corresponding shortest period of rotation is given by T=sqrt((3pi)/(Grho)) where rho is the density of the planet, assumed to be homogeneous. Evalute the rotation period assuming a density of 3.0 gm//cm^(2) , typical of many planets, satellites, and asteroids. No such object is found to be spinning with a period shorter than found by this analysis.

The time period of a sceond's pendulum in a satellite is

The time period of a satellite of the earth is 10 hours. If the separations between the earth and the satellite is increased to 4 times the previous value, then what will be the new time period of the satellite ?

The time period of the satellite of the earth is 5 hours. If the separation between the earth and the satellite is increased to 4 times the previous value,then what will be the new time period of the satellite ?

MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-MHTCET 2009-PHYSICS
  1. In LED visible light is produced by

    Text Solution

    |

  2. The waves which are reflected back to the earth by ionosphere is

    Text Solution

    |

  3. From a disc of radius R, a concentric circular portion of radius r is...

    Text Solution

    |

  4. A 5 m long aluminium wire (Y=7xx10^10(N)/(m^2)) of diameter 3 mm suppr...

    Text Solution

    |

  5. For a given material, Young's modulus is 2.4 times that of rigidity mo...

    Text Solution

    |

  6. If you set up the seven overtone on a string fixed at both ends, how ...

    Text Solution

    |

  7. A car is moving with speed 30m//sec on a circular path of radius 500 m...

    Text Solution

    |

  8. A particle of mass m is rotating in a plane in circular path of radius...

    Text Solution

    |

  9. The unit of Wien 's constant b is

    Text Solution

    |

  10. If rho is the density of the planet , the time period of nearby satell...

    Text Solution

    |

  11. If fringe width is 0.4 mm, the distance between fifth bright and third...

    Text Solution

    |

  12. If 150 J of energy is incident on area 2m^(2) . If Q(r)=15J, coeffici...

    Text Solution

    |

  13. If an electron is revolving around the hydrogen nucleus at a distance ...

    Text Solution

    |

  14. If a simple pendulum oscillates with an amplitude of 50 mm and time pe...

    Text Solution

    |

  15. In hydrogen atom, the electron is making 6.6xx10^(15) rev//sec around ...

    Text Solution

    |

  16. Same current is flowing in two alternating circuits. The first circuit...

    Text Solution

    |

  17. In an AC circuit, the instantaneous values of e.m.f and current are e...

    Text Solution

    |

  18. The periodic time of a particle doing simple harmonic motion is 4 seco...

    Text Solution

    |

  19. For the Bohr's first orbit of circumference 2pi r , the de - Broglie ...

    Text Solution

    |

  20. An alternating voltage E=200sqrt(2)sin(100t) is connected to a 1 micro...

    Text Solution

    |