If a simple pendulum oscillates with an amplitude of 50 mm and time period of 2 sec, then its maximum velocity is

Options

A. `0.10 ms^(-1)`
B. `0.15 ms^(-1)`
C. `0.8 ms^(-1)`
D. `0.26 ms^(-1)`

Answer

B

Explanation

`v_("max")=a omega = a xx (2 pi)/(T)=(50xx10^(-3)) xx (2pi)/(2)`
=`0.15 ms^(-1) `