In hydrogen atom, the electron is making `6.6xx10^(15) rev//sec` around the nucleus in an orbit of radius `0.528 A`. The magnetic moment `(A-m^(2)) will be

Options

A. ` 1 xx 10^(-15)`
B. `1 xx 10^(-10)`
C. `1 xx 10^(-23)`
D. `1 xx 10^(-27)`

Answer

C

Explanation

Current , I `=6.6xx10^(15) xx 1.6xx10^(-19)`
`=10.5xx10^(-4)A `.
Area `A=piR^(2)=3.142 xx (0.528)^(2) xx 10^(-20) m^(2)`
So, Magnetic moment
`M=IA=10.5xx10^(-4) xx 3.142 xx (0.528)^(2) xx 10^(-20)`
`= 10 xx 10^(-24)=10^(-23)` units