The compound from which formic acid cannot be prepared is

Options

A. methyl alcohol
B. carbon monoxide + NaOH
C. glycerol
D. methyl magnesium bromide

Answer

D

Explanation

Formic acid (HCOOH) cannot be prepared from methyl magnesium bromide `(CH_(3)MgBr)` while from all other reagents , it is obtained as
(a) `underset(" methyl alcohol ")(CH_(3)OH) overset([O])to HCHO overset([O])to HCOOH`
(b) `CO+NaOH to HCOONa underset(Delta)overset(NaHSO_(4))to HCOOH+Na_(2)SO_(4)`
(c) Glycerol + Oxalic acid `underset(H_(2)O)overset(383K)toHCOOH`+glycerol