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In a solution , 0.02 M acetic acid is 4%...

In a solution , 0.02 M acetic acid is 4% dissociation . The `[OH^(-)]` in the solution is

A

`8 xx 10^(-4)`

B

`2xx10^(-14)`

C

`8xx10^(10)`

D

`1.25 xx 10^(-11)`

Text Solution

Verified by Experts

The correct Answer is:
D
`[H^(+)]=sqrt(alpha^(2)C^(2))=sqrt((0.02)^(2)*(0.04)^(2))=8xx10^(-4)`
`[H^(+)][OH^(-)]=10^(-14)`
`:. [OH^(-)]=(10^(-14))/(8xx10^(-4))=1.25xx10^(-11)M`
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