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int[sin(logx)+cos(logx)]dx...

`int[sin(logx)+cos(logx)]dx`

A

` x cos( log x )+c`

B

`cos ( log x )+c`

C

`x sin ( logx)+c `

D

`sin ( log x)+c `

Text Solution

Verified by Experts

The correct Answer is:
C
`int[ sin (log x)+ cos ( log x )] dx `
`= int (d)/(dx){x sin ( log x) } dx `
`= x sin ( log x )+c `
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-MHTCET 2009-MATHEMATICS
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