KE per unit volume is E. The pressure exerted by the gas is given by

Options

A. `(E)/(3)`
B. `(2E)/(3)`
C. `(3E)/(2)`
D. `(E)/(2)`

Answer

B

Explanation

The pressure exerted by the gas ,
`p = (1)/(3) rho vecc^(2)`
`= (1)/(3) (m)/(V) vecc^(2)`
`= (2)/(3) ((1)/(2) mvecc^(2))`
`(because (1)/(2) m vecc^(2) = (E)/(V)` = energy per unit volume , V = 1)
`p = (2)/(3) E`