When a current of 2 A is passed through a coil of 100 turns , flux associated with it is `5 xx 10^(-5) `Wb. Find the self inductance of the coil.

Options

A. `4 xx 10^(-3) H`
B. `4 xx 10^-2 H`
C. `2.5 xx 10^(-3) H`
D. `10^(-3)`H

Answer

C

Explanation

Self inductance , `L = (N phi)/(i)`
`= (100 xx 5 xx 10^(-5))/(2)`
`= 250 xx 10^(-5)`
`=2.5 xx 10^(-3) H`