When a rod of length l is rotated with angular velocity of `omega` in a perpendicular field of induction B , about one end , the emf across its ends is

Options

A. `Bl^(2) omega`
B. `(Bl^(2) omega)/(2)`
C. `Bl omega`
D. `(Bl omega)/(2)`

Answer

B

Explanation

A conducting rod of length l whose one end is fixed , is rotated about the axis passing through its fixed end and perpendicular to its length with constant angular velocity `omega`. Magnetic field (B) is perpendicular to the plane of the paper.
Emf induced across the ends of the rod is e = BAn

`= Bpi rl^(2) n`
= `(Bl^(2) pi)/(T)`
`= (1)/(2) Bl^(2) omega`