In a hydrogen atom following the Bohr's postulates the product of linear momentum and angular momentum is proportional to `n^(x)` where 'n' is the orbit number. Then 'x' is:

Options

A. 0
B. 1
C. `-2`
D. 2

Answer

A

Explanation

Linear momentum = mv = `(mcZ)/(137 n)`
Angular momentum = `(nh)/(2pi)`
Given,
Linear momentum `xx` angular momentum `prop n^x`
`therefore (ncZ)/(137n) xx (nh)/(2pi) prop n^(x) `
`n^(0) prop n^(x)`
`implies x = 0`