How many gram equivalents of NaOH are required to neutralize `25 cm^(3)` of decinormal HCl solution ?

Options

A. `0.00125`
B. `0.0025`
C. `0.0050`
D. `0.025`

Answer

B

Explanation

For acid-base reactions ,
g-equivalent of acid (HCL) = g-equivalent of base (NaOH)
`therefore` g-equivalent of acid = `(25 xx 10^(-3)) dm^(3) xx (1)/(10)`
=` 25 xx 10^(-4)`
or = 0.0025
= g-equivalent of NaOH