Home
Class 12
CHEMISTRY
Ratio of loss in solvent to gain in CaCl...

Ratio of loss in solvent to gain in `CaCl_(2)` tube is

A

`(p^(@))/(p)`

B

`(p)/(p^(@))`

C

`(p^(@) - p)/(p^(@))`

D

`(p-p^(@))/(p)`

Text Solution

Verified by Experts

The correct Answer is:
C

`because` Loss in the weight of solvent = `p^(@) - p`
`because` Gain in the weight of `CaCl_(2) ` tube = `p^(@)`
`implies ("Loss in the weight of solvent")/("Gain in the weight of" CaCl_(2) "tube") = (p^(@) - p)/(p^(@))`
Promotional Banner

Topper's Solved these Questions

  • MHTCET 2009

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise CHEMISTRY|50 Videos
  • MHTCET 2011

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise CHEMISTRY|50 Videos

Similar Questions

Explore conceptually related problems

CaCl_(2) is used as

Cacl2

Ionic strength of 0.4 M CaCl_(2) is

Gaining Ratio