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If matrix A=[(a,b),(c,d)], then |A|^(-1)...

If matrix `A=[(a,b),(c,d)]`, then `|A|^(-1)` is equal to

A

ad-bc

B

`(1)/(ad-bc)`

C

`(1)/(ad-bc) [{:(d,-b), (-c, a):}]`

D

None of these

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Verified by Experts

The correct Answer is:
B
Given , A = `[{:(a , b) , (c , d):}]`
`|A| `= ad - bc
`therefore |A|^(-1) = (1)/(ad - bc)`
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