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The equation of the plane which passes t...

The equation of the plane which passes through (2,-3,1) and is normal to the line joining the points (3,4,-1) and (2,-1,5) is given by

A

`x + 5y - 6z + 19 =0`

B

`x - 5y + 6z - 19 = 0 `

C

`x + 5y + 6z + 19 = 0`

D

`x - 5y - 6z - 19 = 0`

Text Solution

Verified by Experts

The correct Answer is:
A
The equation of plane is
`(x - 2) + 5(y + 3) - 6(z-1) = 0`
`implies x + 5y - 6z + 19 = 0`
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