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The angle between the lines in x^2-xy-6...

The angle between the lines in `x^2-xy-6y^2-7x+31y-18=0` is

A

`(pi)/(4)`

B

`(pi)/(6)`

C

`(pi)/(2)`

D

`(pi)/(3)`

Text Solution

Verified by Experts

The correct Answer is:
A
Given equation is
`x^(2) - xy - 6y^(2) - 7x + 31y - 18 = 0`
Here , a = 1 , b = -6 , h = `(1)/(2)`
`therefore theta = tan^(-1) |(2sqrt(((-1)/(2))^(2)) - 1 xx (-6))/(1 + (-6))|`
`= tan^(-1) |(2sqrt((1)/(4) + 6)/(-5))|`
`= tan^(-1) |-1|`
`= (pi)/(4)`
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