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A particle executes a simple harmonic mo...

A particle executes a simple harmonic motion of time period T. Find the time taken by the particle to go directly from its mean position to half the amplitude.

A

T/2

B

T/4

C

T/8

D

T12

Text Solution

Verified by Experts

The correct Answer is:
D
`y=asin omegat=(a sin 2pi)/(T)t`
At the mean position `y=a/2`
`a/2=(asin 2pit)/(T)`
`t=T/12`
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