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Two springs have their force constants `K_(1)` and `K_(2)` and they are stretched to the same extension. If `K_(2) gt K_(1)` work done is

A

more is spring A

B

more in speing B

C

equal in both

D

nothing can be said

Text Solution

Verified by Experts

The correct Answer is:
A
Work done is stretching (W) = stiffness of speing
`because K_(A) gt K_(B), W_(A)gt W_(B)`
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