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For the stationary wave y=4sin((pix)/(15...

For the stationary wave `y=4sin((pix)/(15))cos(96pit)`, the distance between a node and the next antinode is

A

7.5

B

15

C

22.5

D

30

Text Solution

Verified by Experts

The correct Answer is:
A
On comparing given equation with standard equation, we get
`(2pi)/(lamda)=(pi)/(15)`
`implieslamda=30`
Distance between the node and antinode
`=lamda/4`
`(30)/(4)=7.5`
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