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In a resonance tube the first resonance ...

In a resonance tube the first resonance with a tuning fork occurs at 16 cm and second at 49 cm . If the velocity of sound is 330 m/s , the frequency of tuning fork is

A

500

B

300

C

330

D

165

Text Solution

Verified by Experts

The correct Answer is:
A
For closed pipe `l_(1)=(v)/(4n)and l_(2)=(3v)/(4n)`
`v=2n(l_(2)-l_(1))`
`n=(n)/(2(l_(2)-l_(1)))=(330)/(2xx(0.49-0.16))=500Hz`
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