In Young's double slit experiment, if the slit widths are in the ratio `1:9`, then the ratio of the intensity at minima to that at maxima will be

Options

A. 1
B. `1//9`
C. `1//4`
D. `1//3`

Answer

C

Explanation

Amplitude of the superimposing waves are
`(a_(1))/(a_(2))=((1)/(9))^(1//2)=1/3`
`(I_("minima"))/(I_("Maxima"))=((a_(1)-a_(2))^(2))/((a+_(1)+a_(2))^(2))=1/4`