If the distance between the plates of a parallel plate capacitor of capacity of `muF` is doubled, then new capacity will be

Options

A. `5 mu F`
B. `2
C. 0 muF`
D. `10muF`

Answer

A

Explanation

In parallelplate capacitor
`C=epsi_(0)A/d" "...(i)`
Now, `d'=24`
Hence, `C'=(epsi_(0)A)/(d')=(epsi_(0)A)/(2d)" "...(ii)`
From Eqs. (i) and (ii)
`(C')/(c )=1/2`
`C'=C/2`
Putting `C=10muF`
`C'=10/2=5 muF`