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What will be the self inductance of a co...

What will be the self inductance of a coid of 100 turns if a current of 5 A produces a magnetic flux `5xx10^(-5)` Wb?

A

1 mH

B

10 mH

C

`1 muH`

D

`10 muH`

Text Solution

Verified by Experts

The correct Answer is:
A
Self inductance `L=(N phi)/(I)`
`L=(100xx5xx10^(-5))/(5)=10^(-3)H`
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