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When Zn is treated with excess of NaOH, ...

When `Zn` is treated with excess of `NaOH`, the product obtained is

A

`Zn(OH)_(2)`

B

`ZnOH`

C

`Na_(2)ZnO_(2)`

D

`"None of the above"`

Text Solution

Verified by Experts

The correct Answer is:
C
When Zn is reacted with excess of NaOH, sodium zincate is obtained.
`Zn+2NaOH+2H_(2)Oto Na_(2)underset("soluble")([Zn(OH)_(4)])+H_(2)`
or `An+2NaOHto Na_(2)ZnO_(2)+H_(2)`
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