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If f(x)=e^(x)g(x),g(0)=2,g'(0)=1, then f...

If `f(x)=e^(x)g(x),g(0)=2,g'(0)=1, then f'(0) ` is

A

1

B

3

C

2

D

0

Text Solution

Verified by Experts

The correct Answer is:
B
`f'(x)=e^(x)g'(x)+e^(x)g(x)`
`impliesf'(0)=e^(0)*g'(0)+e^(0)g(0)`
`=1*1+1*2`
`[because{g'(0)=1and g(0)-2}]=1+2=3`
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