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y=logtan(x/2)+sin^(-1)(cosx), then dy/dx...

`y=logtan(x/2)+sin^(-1)(cosx)`, then `dy/dx` is

A

`cosec x-1`

B

`cosec x`

C

`cosec x+1`

D

x

Text Solution

Verified by Experts

The correct Answer is:
A
`(dy)/(dx)=(1)/(tan x//2)sec ^(2)""(x)/(2)*(1)/(2)+ (1)/(sqrt(1 - cos^(2) x))"(-sin x)"`
`(1)/(2sin ""(x)/(2)*cos ""(x)/(2))1=cosecx-1`
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