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The integrating factor of the differenti...

The integrating factor of the differential equation `(dy)/(dx)(x(log)_e x)+y=2(log)_e x` is given by

A

`e^(x)`

B

log x

C

log (log x)

D

x

Text Solution

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The correct Answer is:
B
`(dy)/(dx)(x log x)+y=2 logx`
`implies(dy)/(dx)+(y)/(x log x)=2/x`
Here `P=(1)/(x log x),Q=2/x`
`therefore` If `=^(eint pdx=eint (dx)/(x logx))=x`
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