If the conductance and capacitance are both doubled in L-C-R circuit, the reonant frequency of the circuit will.

Options

A. decrease to twice the original value
B. decrease to one - fourth the original value
C. increase to twice the original value
D. decreases to one - half the original value

Answer

D

Explanation

The resonant frequency
` v _ 0 = ( 1 )/( 2pi sqrt ( LC )) rArr v _ 0 prop ( 1 )/( sqrt ( LC)) `
If condutance and capictance both are doubled, then
` v _ 0 = ( 1 ) /( 2 ) ( ( 1 ) /( 2pi ) sqrt ( LC)) `
So, the resonant frequency will decrease to one- half of the original value.