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The degree of ionization of 0.4 M ac...

The degree of ionization of 0.4 M acetic acid will be ` ( K _ a = 1.8 xx 10 ^( -5 )) `

A

` 6.71 xx 10 ^( -3 ) `

B

` 1.6 xx 10 ^( - 3 ) `

C

` 0.4 xx 1.8 xx 10^( - 5 ) `

D

`1.8 xx 10 ^( - 5 ) `

Text Solution

Verified by Experts

The correct Answer is:
A
For a weak acid ( acetic acid )
` K _ a = Calpha ^ 2 `
`1.8 xx 10 ^( - 5 ) = 0.4 xx alpha ^ 2 `
` alpha = sqrt (( 1.8 xx 10 ^( -5))/(0.4 )) `
` = 6.71 xx 10 ^( -3 ) `
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