What is the volume of water consumed during acid hydrolysis of 1.368 kg of surose ?

Options

A. 0.072 `dm^(3)`
B. 0.72 `dm^(3)`
C. 0.18 `dm^(3)`
D. 0.018 `dm^(3)`

Answer

a

Explanation

`"Sucrose" +H_(2)OrarrC_(6)H_(12)O_(6)+c_(6)H_(12)O_(6)`
`because` 342 g sucrose consume =18 g `H_(2)O`
`therefore` 1 g sucrose consume `=(18)/(342) g H_(2)O`
`therefore 1.368 xx1000g` sucrose consume
`=18/342xx1.368xx1000=72 g H_(2)O`
Now given density of `H_(2)O=1 g/cm^(3)` and we know
`d=(m)/(v)`
`v=(m)/(d)=(72g)/(1g//cm^(3))=72 cm^(3)=0.072 dm^(3)`