If, an electron in hydrogen atom jumps from an orbit of lelvel n=3 to an orbit of level n=2, emitted radiation has a freqwuency (R= Rydbertg's contant ,c = velocity of light)

Options

A. `(3R_(C))/(27)`
B. `(R_(C))/(25)`
C. `(8R_(C))/(9)`
D. `(5 R_(C))/(36)`

Answer

D

Explanation

When an electron jumps from orbit `n_(i)` to orbit `n_(f) )(n_(i) gt n_(t))` , the frequency of emitted photon is given by
`v = cR [ (1)/(n_(f)^(2)) - (1)/(n_(i)^(2))] implies v = cR [ (1)/(2^(2)) - (1)/(3^(2))]`
v = `cR [ (5)/(36)] implies v = (5 cR)/(36)`