The relation between force `F` and density `d` is `F=(x)/(sqrt(d))`.
The dimension of `x` is

Options

A. `[L^(-1//2) M^(3//2) T^(-2)]`
B. `[L^(-1//2) M^(1//2) T^(-2)]`
C. `[L^(-1) M^(3//2) T^(-2)]`
D. `[L^(-1) M^(1//2) T^(-2)]`

Answer

A

Explanation

Given `, F = (x)/(sqrtd)`
Substituting dimensions
`MLT^(2) = (x)/(sqrt(ML^(-3)))`
`implies x = [M^(3//2) L^(-1//2) T^(2)]`