If the end correction of an open pipe is 0.8 cm, then the inner radius of that pipe will be

Options

A. `1/3`cm
B. `2/3` cm
C. `3/2` cm
D. 0.2cm

Answer

C

Explanation

For an open organ pipe, the relation between end correction and inner radius of the organ pipe is given by
`Deltal=1.2xxr`
[`Deltal` end correction, r= inner radius]
So, `r=(Deltal)/1.2=(0.8)/1.2` `[because Deltal = 0.8]`
`2/3cm`