The value of gravitational accelerationg at a height h above the earth's surface is then (R = radius of earth)

Options

A. h=R
B. `h=R/2`
C. `h=R/3`
D. `h=R/4`

Answer

A

Explanation

The value of acceleration due to gravity g at a height h is given by `g^'=g(R_e/(R_e+h))^2` [Symbols have their usual meanings]
When,
g^'=g/4and R_e=R`
So, g/4=g(r/(R+h))^2
`1/2=R/(R+h)`
`Rightarrow 2R=R+h`
Rightarrow R=h