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What is the amount of work done when 0.5...

What is the amount of work done when 0.5 mole of methane, `CH_(4)`(g) is subjected to combustion at 300 K? (given, `R=8.314 Jk^(-1) mol^(-1))`

A

` -2494 J`

B

`-4988 J`

C

` + 4988 J`

D

`+2494 J`

Text Solution

Verified by Experts

The correct Answer is:
D
0.5CH_4(g)+O_2to0.5CO_2(g)+H_2O(l)`
`Deltan=0.5-1.5=-1`
Work done `=-DeltanRT=-(-1)^**8.314xx30=2494J`
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