The equation of line equally inclined to coordinate axes and passing through (-3,2,-5) is

Options

A. `(x+3)/(-1) = (y-2)/(1) = (z+5)/(1)`
B. `(x+3)/(-1) = (y-2)/(1) = (5+z)/(-1)`
C. `(x+3)/(-1) = (y-2)/(1) = (z+5)/(-1)`
D. `(x+3)/(-1) = (2-y)/(1) = (z+5)/(-1)`

Answer

B

Explanation

Let `(x_(1),y_(1),z_(1)) -= (-3,2,-5)`
It is also given that, the line is equally inclined to coordinate axes.
`:. L = - 1, m = 1` and `n = - 1`
We know that, the equation of line passing through `(x_(1),y_(1),z_(1))` and having direction consines l,m,n is
`(x-x_(1))/(l) = (y-y_(1))/(m) = (z-z_(1))/(n)`
`:. (x+3)/(-1) = (y-2)/(1) = (z+5)/(-1)`