Home
Class 12
PHYSICS
The path length of oscillation of simple...

The path length of oscillation of simple pendulum of length 1 m is 16 cm. Its maximum velocity is (take, `g=pi^(2)m//s^(2)`)

A

`2picm//s`

B

`4picm//s`

C

`8picm//s`

D

`16picm//s`

Text Solution

Verified by Experts

The correct Answer is:
C
Given,
Length of the pendulum `(l)=1m`
`:.` Amplitude `(a)=("Path length")/(2)=(16)/(2)=8cm`
Acceleration due to gravity `(g)=pi^(2)m//s^(2)`
We know that, time period `(T)=2pisqrt((l)/(g))=2pisqrt((1)/(pi^(2)))`
`T=(2pi)/(pi)`
`T=2s`
`:.` Maximum velocity `(v_(max))=aomega`
`=axx(2pi)/(T)" "(becauseomega=(2pi)/(T))`
`=(8xx2xxpi)/(2)8picm//s`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • MHTCET 2017

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise PHYSICS|50 Videos

  • MHTCET 2019 PAPER 1

    MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS|Exercise PHYSICS|50 Videos

Similar Questions

Explore conceptually related problems

The periodic time of a simple pendulum of length 1 m and amlitude

The time period of a simple pendulum of length 1 m is _______ second. (take pi^(2)=10,g=10ms^(-2) )

Knowledge Check

  • IF the length of a simple pendulum is increased, its maximum velocity during oscillation

    A
    decreases
    B
    increases
    C
    remains same
    D
    is zero

  • A simple pendulum 50cm long is suspended from the roof of a acceleration in the horizontal direction with constant acceleration sqrt(3) g m//s^(-1) . The period of small oscillations of the pendulum about its equilibrium position is (g = pi^(2) m//s^(2)) ltbRgt

    A
    `1.0 sec`
    B
    `1.25 sec`
    C
    `1.53 sec`
    D
    `1.68 sec`

  • A graph is drawn between the displacement and time taken for the oscillations of a simple pendulum. The length of the pendulum is _______ m (if g=10ms^(-2)andpi^(2)=10 )

    A
    2
    B
    1
    C
    0.5
    D
    0.25

    • Similar Questions

    Explore conceptually related problems

    The time period of a simple pendulum of length 1 m is _____ second. ( take pi^(2) = 10.g =10 ms^(-2) )

    For oscillation of a simple pendulum of length L what is the maximum possible velocity at the lowest position What happens to the motion if velocity exceeds this value ?

    The time t of a complete oscillation of a simple pendulum of length l is given by the equation T=2 pi sqrt((1)/(g)) where g is constant.What is the percentage error in T when l is increased by 1%?

    A graph is drawn between the displacement and time taken for the oscillations of a simple pendulum. The length of the penddulum is _______ m ( if g = 10 s^(-2) and pi^(2) =10 )

    A graph is drawn between the displacement and time taken for the oscillations of a simple pendulum. The length of the pendulum is ________ m (if g=10ms^(-2)andpi^(2)=10 ).

    Home
    Profile