A transistor is used as a common emitter amplifier with load resistance `2kOmega`. The changed by `20muA` which results in a change in collector current by 1.5 mA. The voltage gain of the amplifier is

Options

A. 900
B. 1000
C. 1100
D. 1200

Answer

B

Explanation

Given, load resistance `(R_(e))=2kOmega=2xx10^(3)Omega`
Input resistance `(R_(i))=150Omega`
Change in collector current `(Deltal_(c))=1.5mA`
`=1.5xx10^(-3)A`
Change in base current `(Deltal_(B))=20xx10^(-6)A`
We know that,
voltage gain `=(V_(o))/(v_(i))=(R_(o)xxDeltal_(c))/(R_(i)xxDeltal_(B))`
`=(2xx10^(-3)xx1.5xx10^(-3))/(150xx20xx10^(-6))=(3xx10^(6))/(150xx20)`
`=1000`