For a particle performing linear SHM, its average speed over one oscillation is (where, a= amplitude of SHM, n=frequency of oscillation)

Options

A. 2 an
B. 4 an
C. 6 an
D. 8 an

Answer

B

Explanation

Given, amplitude of SHM =a Frequency of oscillation = n
Distance travellled in one oscillation,
`=4xx` amplitude of SHM =4a
We know that,
Velocity `=("Distance travelled in one oscillation")/("Time period")`
`v=(4a)/(T)`
`:." "v=4an" "[because" Frequency," n=(1)/(T)]`