An ideal transformer converts 220 V AC to 3.3 kV AC to transmit a power of 4.4 kW. If primary coil has 600 turns, then alternating current in secondary coil is

Options

A. `(1)/(3)A`
B. `(4)/(3)A`
C. `(5)/(3)A`
D. `(7)/(3)A`

Answer

B

Explanation

Given, input voltage `(V_(P))=220V`
Output voltage `(V_(S))=3.3xx10^(3)V`
Power `(P)=4.4kW=4.4xx10^(3)W`
Number of turns in primary coil = 600
We know that,
For an ideal transformer, `(V_(S))/(V_(P))=(I_(P))/(I_(S))`
`I_(S)=I_(P)xx(V_(P))/(V_(S))`
`I_(S)=(20xx220)/(3.3xx10^(3))`
`I_(S)=(44)/(33)=(4)/(3)A`