A bomb at rest explodes into 3 parts of same mass. The momentum of two parts is `-3phat(i)and2phat(j)`. Respectively. The magnitude of momentum f the third part is

Options

A. p
B. `sqrt(5)p`
C. `sqrt(11)p`
D. `sqrt(13)p`

Answer

D

Explanation

According to the question, we get can draw the following diagram. Now, the magnitude of momentum of the third part is given by
`p_(3)=sqrt((p_(1)^(2))+(p_(2))^(2))`
`p_(3)=sqrt((-3p)^(2)+(2p)^(2))`
`p_(3)=sqrt(9p^(2)+4p^(2))`
`p_(3)=sqrt(13p^(2))`
`:." "p_(3)=sqrt(13)p`