A pipe closed at one end has length 83 cm. The number of possible natural oscilations of air column whose frequencies lie below 1000 Hz are (take, velocity of sound in air 332 m/s)

Options

A. 3
B. 4
C. 5
D. 6

Answer

C

Explanation

Fundamental frequency of one closed pipe,
`V=(nv)/(4L)`
Here, `n=1`
`or" "v_(1)=(332)/(4xx83xx10^(-2))`
`or" "v_(1)=100`
As odd harmonics alone are produced in closed organ pipe, therefore possible frequencies are
`3v_(1)=300Hz,5v_(2)=500Hz`,
`7v_(2)=700Hz,9v_(2)=900Hz`
Hence, the number of possible natural oscillation of air colume is 5.