A certain reaction ocuurs in two steps as
(I) `2SO_(2(g))+2NO_(2(g)) to 2SO_(3(g))+2NO_((g))`
`(ii) 2NO_((g) ) +O_(2) (g) to 2NO_(2(g))`
In the reaction ,______.

Options

A. `NO_(2)(g)` is intermediate
B. `NO(g)` is intermediate
C. `NO(g)` is catayst
D. `O_(2)(g)` is intermediate

Answer

B

Explanation

Given
Step I :
`2SO_(2)(g)+2NO_(2)(g)to2SO_(3)(g)+@NO(g)`
Step II : `2NO(g)+O_(2)(g)to2NO_(2)(g)`
An intermediate formed in the reaction is not a part of overall reaction.
Net reaction : `2SO_(2)(g)+O_(2)(g)to2SO_(3)(g)`
As, No(g) formed in first elementary step is neither a reactant nor product in the net reaction. It is formed in one elmentary step and consumed in the next step. Thus NO,=(g) act as an intermediate.