Formation of `PCl_(3)` is explained on the basis of what hybridisation of phosphorus atom?

Options

A. `sp^(2)`
B. `sp^(3)`
C. `sp^(3)d`
D. `sp^(3)d^(2)`

Answer

B

Explanation

The type of hybridisation in an atom can be determined by using the formula
`H=(1)/(2)[V+Y-C+A]`
Here, V = valence shell electrons of the central atom
Y=number of monovalent atom
C=total positive charge
and A=total negatice charge
In case of `PCl_(3)`,
`H=(1)/(2)[5+3]=4`
`:.` Hybridisation of phosphorus atom is `sp^(3)`

Pyramidal shape (due to presence of one lone pair of electron.