The number of moles of electrons passed when current of 2 A is passed through an solution of electrolyte for 20 minutes is ___________.

Options

A. `4.1xx10^(-4)"mole"^(-)`
B. `1.24xx10^(-2)"mole"^(-)`
C. `2.487xx10^(-2)"mole"^(-)`
D. `2.487xx10^(-1)"mole"^(-)`

Answer

C

Explanation

Given, I=2A, and t=20 min, i.e. 1200s
As we know, `Q=l*t`
`Q=2Axx1200s`
`=2400A-s=2400C`
Using, Q=ne
where, Q=quantity of charge
n=number of electrons
`e=1.6xx10^(-19)C`
So, `Q=nxx1.6xx10^(-19)C`
`n=(2400C)/(1.6xx10^(-19)C)=1.5xx10^(22)`
The number of electrons passed when current 2A is passed through a solution of electrolyte for 20 min is `1.5xx10^(22)`.
Number of moles of electrons `=(1.5xx10^(22))/(6.022xx10^(23))`
`2.487xx10^(-2)"mole e"^(-)`