Identify the oxidation states of titinium (Z=22) and copper (Z=29) in their colourless compounds.

Options

A. `Ti^(3+),Cu^(2+)`
B. `Ti^(2+),Cu^(2+)`
C. `Ti^(4+),Cu^(+)`
D. `Ti^(4+),Cu^(2+)`

Answer

C

Explanation

Electronic configuration of titanium (Ti) (Z=22) is `[Ar]_(18)3d^(2)4s^(2)`. In case of `Ti^(4+)`, the electronic configuration will be `[Ar]_(18)3d^(0)4s^(0)`
Similarly, electronic configuration of copper (Cu) (Z=29) is `[Ar]_(18)3d^(10)4s^(1)`. On loosing one electron it acquires stable electronic configuration, i.e `[Ar]_(18)3d^(10)`.
In both `Ti^(4+)` and `Cu^(+)` no unpaired electron is present. As a result, no d-d transition occur and therefore these are colourless in nature.