The cartesian coordinates of the point on the parabola `y^(2)=-16x`, whose parameter is `(1)/(2)`, are

Options

A. `(-2,4)`
B. `(4,-1)`
C. `(-1,-4)`
D. `(-1,4)`

Answer

C

Explanation

We know that paramentric from of `y^(2)=4ax` is
`x=at^(2)andy=2at`
Here, `y^(2)=-16x`
`:." "x=-4t^(2)andy=-8t`
Given, `t=(1)/(2)`
`:." "x=-4((1)/(2))^(2)andy=-8((1)/(2))`
`x=-1andy=-4`
Hence, cartesian coordinates are `(-1,-4)`.