The line `5x+y-1=0` coincides with one of the lines given by `5x^(2)+xy-kx-2y+2=0`, then the value of k is

Options

A. `-11`
B. 31
C. 11
D. `-31`

Answer

C

Explanation

Given, 5x+y-1=0 coincides with one of the lines given by `5x^(2)+xy-kx-2y+2=0`
On putting the value of `y=-5x+1` in the above equation,
we get
`5x^(2)+x(-5x+1)-(kx-2(-5x+1)+2=0` ltbrlt`rArr" "5x^(2)-5x^(2)+x-kx+10x-2+2=0`
`rArrx-kx+10x=0`
`rArr11x-kx=0`
`rArr11-k=0`
`k=11`